x^2/5=w+y

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Solution for x^2/5=w+y equation: 


x in (-oo:+oo)

(x^2)/5 = w+y // - w+y

(x^2)/5-w-y = 0

1/5*x^2 = -(-w-y) // : 1/5

x^2 = 5*(w+y)

x^2 = 5*(w+y) // ^ 1/2

abs(x) = 5^(1/2)*(w+y)^(1/2)

x = 5^(1/2)*(w+y)^(1/2) or x = -(5^(1/2)*(w+y)^(1/2))

x in { 5^(1/2)*(w+y)^(1/2), -(5^(1/2)*(w+y)^(1/2)) }

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